If a straight line I passing through P(3,4) meets positive co-ordinate axes at A &B such that area of triangle OAB is minimum (where O is origin) then slope of I is

If a straight line L with negative slope passing through (8,1) meets the coordinate axes at A and B then minimum value of OA+OB is

A line is drawn passing through point P(1,2) to cut positive coordinate axes at A and B . Find minimum area of DeltaPAB .

A straight line passing through P(3,1) meets the coordinate axes at Aa n dB . It is given that the distance of this straight line from the origin O is maximum. The area of triangle O A B is equal to (50)/3s qdotu n i t s (b) (25)/3s qdotu n i t s (20)/3s qdotu n i t s (d) (100)/3s qdotu n i t s

A straight line with negative slope passing through the point (1,4) meets the coordinate axes at A and B.The minimum value of OA+OB is equal to

A line is drawn through the point (1,2) to meet the coordinate axes at P and Q such that it forms a triangle OPQ ,where 0 is the origin.If the area of the triangle OPQ is least,the slope of the line PQ is k ,then |k| =

Equation of a straight line passing through (1,4) if the sum of its positive intercepts on the co-ordinate axes is the smallest is :

A line is drawn through the point (1,2) to meet the coordinate axes at P and Q such that it forms a triangle OPQ,where O is the origin. If the area of the triangle OPQ is least,then the slope of the line PQ is (1) -(1)/(4) (2) -4(3)-2(4)-(1)/(2)