From the point (2, 2) tangent are drawn to the hyperbola `(x^2)/(16)-(y^2)/9=1.` Then the point of contact lies in the first quadrant (b) second quadrant third quadrant (d) fourth quadrant

From the point (2, 2) tangent are drawn to the hyperbola (x^2)/(16)-(y^2)/9=1. Then the point of contact lies in the (a)first quadrant (b) second quadrant (c)third quadrant (d) fourth quadrant

From the point (2, 2) tangent are drawn to the hyperbola (x^2)/(16)-(y^2)/9=1. Then the point of contact lies in the (a) first quadrant (b) second quadrant (c) third quadrant (d) fourth quadrant

From the point (2, 2) tangent are drawn to the hyperbola (x^2)/(16)-(y^2)/9=1. Then the point of contact lies in the (a) first quadrant (b) second quadrant (c) third quadrant (d) fourth quadrant

A point whose abscissa is -3 and ordinate 2 lies in First quadrant (b) Second quadrant Third quadrant (d) Fourth quadrant

Does the point (0,2) lie on the first quadrant?

The point (-2,3) lies in the quadrant :

Find the equation of the tangent to the hyperbola: 9x^2-16y^2=144 at the point L of latus rectum in the first quadrant.

The point (2, -3) lies in the quadrant :

The point (-2,7) lies is the quadrant .