Home
Class 11
MATHS
If the coefficients of three consecutive...

If the coefficients of three consecutive terms in the expansion of `(1+x)^n` are in the ratio 1:7:42, then find the value of `ndot`

Text Solution

Verified by Experts

Let the consecutive terms be T1​,T2​,T3​
Hence
`=>7n_(C_r )​=>n_(C_(r+1) )`
`=>7/(n-r)​=1/(r+1)`
​ `=>7r+7=n−r`
`=>n−8r=7 ...(i)`
Also
...
Promotional Banner

Similar Questions

Explore conceptually related problems

The coefficients of three consecutive terms in the expansion of (1+x)^(n) are in the ratio 1:7:42. Find n.

The coefficients of three consecutive terms in the expansion of (1+a)^(n) are in the ratio 1:7:42. Find n.

The coefficient of three consecutive terms in the expansion of (1 + x)^(n ) are in the ratio 1 : 6 : 30. Find n.

If the coefficients of three consecutive terms in the expansion of (1 + x)^(n) are in the ratio 1 : 3 : 5, then show that n = 7.

The coefficients of three consecutive terms in the expansion of (1+x)^(n) are in the ratio 182:84:30. prove that n=18

If the coefficient so three consecutive terms in the expansion of (1+x)^(n) be 76,9 and 76 find n .

If for some positive integer n, the coefficients of three consecutive terms in the binomial expansion (1+x)^(n+5) are in the ratio 5:10:14 , then the largest coefficient in this expansion is :

If the coefficients of the three successive terms in the binomial expansion of (1+x)^(n) are in the ratio 1:4.42 then the first of these terms in the expansion is