Home
Class 11
MATHS
If the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1...

If the ellipse `(x^2)/(a^2)+(y^2)/(b^2)=1` is inscribed in a rectangle whose length to breadth ratio is `2:1` , then the area of the rectangle is `4.(a^2+b^2)/7` (b) `4.(a^2+b^2)/3` `12.(a^2+b^2)/5` (d) `8.(a^2+b^2)/5`

Promotional Banner

Similar Questions

Explore conceptually related problems

If the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1 is inscribed in a rectangle whose length to breadth ratio is 2:1 , then the area of the rectangle is (a) 4.(a^2+b^2)/7 (b) 4.(a^2+b^2)/3 (c) 12.(a^2+b^2)/5 (d) 8.(a^2+b^2)/5

Area of a rectangle with length 4ab and breadth 6b ^(2) is

If area of the ellipse (x^(2))/(16)+(y^(2))/(b^(2))=1 inscribed in a square of side length 5sqrt(2) is A, then (A)/(pi) equals to :

If area of the ellipse (x^(2))/(16)+(y^(2))/(b^(2))=1 inscribed in a square of side length 5sqrt(2) is A, then (A)/(pi) equals to :

The length of a rectangle is y xx its breadth x .The area of the rectangle is: xy(b)xy^(2)(c)x^(2)y(d) None of these

If the area of the ellipse ((x^2)/(a^2))+((y^2)/(b^2))=1 is 4pi , then find the maximum area of rectangle inscribed in the ellipse.

If the area of the ellipse ((x^2)/(a^2))+((y^2)/(b^2))=1 is 4pi , then find the maximum area of rectangle inscribed in the ellipse.

If the area of the ellipse ((x^2)/(a^2))+((y^2)/(b^2))=1 is 4pi , then find the maximum area of rectangle inscribed in the ellipse.

If the area of the ellipse ((x^2)/(a^2))+((y^2)/(b^2))=1 is 4pi , then find the maximum area of rectangle inscribed in the ellipse.

A rectangle is inscribed in an equilateral triangle of side length 2a units. The maximum area of this rectangle can be (a) sqrt(3)a^2 (b) (sqrt(3)a^2)/4 a^2 (d) (sqrt(3)a^2)/2