cot(A)/(2)=(1+cos beta)/(1-cos A)

Prove that: ((1+cot 60)/(1-cot 60))^2=(1+cos 30)/(1-cos 30)

If alpha and beta are complementary angles, then show that cot beta+cos beta= (cos beta)/(cos alpha) (1+sin beta) .

If cos theta=(cos alpha-cos beta)/(1-cos alpha cos beta), prove that tan theta/2=+-tan alpha/2 cot beta/2.

If cos theta=(cos alpha-cos beta)/(1-cos alpha*cos beta), prove that tan(theta)/(2)=+-(tan alpha)/(2)(cot beta)/(2)

If cos theta=(cos alpha-cos beta)/(1-cos alpha cos beta), prove that (tan theta)/(2)=+-(tan alpha)/(2)(cot beta)/(2)

If cos theta=(cos alpha-cos beta)/(1-cos alpha cos beta), prove that tan theta/2=+-tan alpha/2 cot beta/2.

If cos theta=(cos alpha-cos beta)/(1-cos alpha cos beta), prove that tan theta/2=+-tan alpha/2 cot beta/2.

alpha and beta are acute angles and cos2 alpha=(3cos2 beta-1)/(3-cos2 beta) then tan alpha cot beta=

If alpha and beta are acute angles satisfying cos2 alpha=(3cos2 beta-1)/(3-cos2 beta), then tan alpha=sqrt(2)tan beta (b) (1)/(sqrt(2))tan beta(c)sqrt(2)cot beta(d)(1)/(sqrt(2))cot beta