5+arc theta-4=0quad d(5sin theta-4cos theta)/(5sin theta+4cos theta)

If 5tan theta-4=0, then the value of (5sin theta-4cos theta)/(5sin theta+4cos theta) is (5)/(3)(b)(5)/(6)(c)0(d)(1)/(6)

If 5tan theta=4, then (5sin theta-3cos theta)/(5sin theta+2cos theta) is equal to 0 (b) 1 (c) (1)/(6)(d)6

If 5 sin theta-4 cos theta=0, 0^@ < theta<90^@ , then the value of (5sin theta-2 cos theta)/(5sin theta+3 cos theta) is:

If theta lies in the first quadrant and 5tan theta=4 then (5sin theta-3cos theta)/(sin theta+2cos theta)=

If 5tan theta=4 then value of ((5sin theta-3cos theta)/(5sin theta+3cos theta))=

If tan theta = 1 then find the value of (5 sin theta + 4 cos theta)/(5 sin theta - 4 cos theta)

4 sin 5 theta cos 3 theta sin 2 theta

If 5 tan theta =4, find the value of (5 sin theta - 3 cos theta)/(5 sin theta +2 cos theta)