Home
Class 12
CHEMISTRY
DeltaG=DeltaH-TDeltaS and ltBRgt DeltaG...

`DeltaG=DeltaH-TDeltaS` and ltBRgt `DeltaG=DeltaH+T[(d(DeltaG))/(dT)]_(p),` then` ((dE_(cell))/(dT))` is

Promotional Banner

Similar Questions

Explore conceptually related problems

DeltaG=DeltaH-TDeltaS and DeltaG=DeltaH+T[(d(DeltaG))/(dT)]_(p), then ((dE_(cell))/(dT)) is

DeltaG = DeltaH-TdeltaS and DeltaG = DeltaH + T[(d(DeltaG))/(dT)] " then " ((dE_("cell"))/(dT)) is

DeltaG = DeltaH - TDeltaS and DeltaG + T[(d(DeltaG))/(dT)]_(p) then ((dE_(cell)/(dT)) is:

If DeltaG=DeltaH-TDeltaS and DeltaG = DeltaH+T[(d(DeltaG))/(dT)] , then variation EMF of a cell E, with temperature T, is given by

The cell potential (E_("cell")) of a reaction is related as DeltaG = -nFE_("cell") , where DeltaG represents max. useful electrical work . n=no. of moles of electrons exchanged during the reactino of reversible cell reaction d(DeltaG) = (DeltaV)dP-(DeltaS).dT at constant pressure d(DeltaG) = - (DeltaS).dT :' At constant pressure DeltaG = DeltaG = DeltaH-TDeltaS .......(1) :. DeltaG = DeltaH + T((d(DeltaG))/(dT))_P ......... (B) ((dE_("cell"))/(dT))_(P) is known as temperature coefficient of the e.m.f of the cell When DeltaS increases, temperature coefficient of the emf of cell

Establish DeltaG = DeltaH- TDeltaS .

The relation DeltaG=DeltaH-TDeltaS was given by

Derive the equation, DeltaG = DeltaH - T DeltaS .