If f(t) = `1/(t^(2)-t-6) and t = 1/(x-2)` then the values of x which make the function f discontinuous are

If y = frac(1)(t^2-t-6 and t = frac(1)(x-2) then the values of x which make the function y discontinuous, are

If y=(1)/(t^(2)+t-2), where t=(1)/(x-1), then find the number of points where f(x) is discontinuous.

If y=1/(t^2+t-2),where \ t=1/(x-1), then find the number of points where f(x) is discontinuous.

If y=1/(t^2+t-2),where \ t=1/(x-1), then find the number of points where f(x) is discontinuous.

If f(t)=(1-t)/(1+t) then the value of f'(1/t) is

If a function y=f(x) is defined as y=(1)/(t^(2)-t-6)and t=(1)/(x-2), t in R . Then f(x) is discontinuous at

If a function y=f(x) is defined as y=(1)/(t^(2)-t-6)and t=(1)/(x-2), t in R . Then f(x) is discontinuous at

If int_(0)^(x)f(t)dt=x+int_(x)^(1)f(t)dt ,then the value of f(1) is

Given f(x) = 2/(x + 1) , what is(are) the real value(s) of t for which f(t) = t ?