x+2y=-1;2x-3y=12(i

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(3) x+2y=-1;2x-3y=12

Solve the following simultaneous equations using Cramer's rule. x+2y=-1,2x-3y=12 .

2x+3y=12;x-y=1

Solve the following system of by the method of substitution (i)x + 2y = -1 ; 2x - 3y = 12

,x-y=-1, 3x-2y=12

The system of equations x+2y=3,2x-3y=5 and x -12y =1 has

1 + 5x + 3y = 9 2x 3y = 12 X = (x, y) - 4

Show that x = 3 and y = -2 is the solution of the system of linear equations x+2y=-1" and "2x-3y=12 .

The circles x^2+y^2-12x-12y=0 and x^2+y^2+6x+6y=0 :