[x+y+z=3],[2x-y+z=-1],[2x+y-3z=-9]

x+y+z=4 2x-y+z=-1 2x+y-3z=-9

2x+y+z=1x-y+2z=-1,3x+2y-z=4

The equations x+2y-z=3, 3x-y+2z=1, 2x-2y+3z=2 have

Solve by matrix method 2x +y +z=1 x-2y-z =3//2 3y-5z =9

Statement - I The soluton of the system of equations 2x-y+3z=9,x+y+z=6,x-y+z=2 is x=1,y=2,z=3 Statement - II : The solution of the system of equations x+2y-z=3,3x=y+2z=1 , 2x-2y+3z=2 is x=-1,y=4,z=4 Which of the above Statement(s) is true ?

Show that : |[x, y, z ],[x^2,y^2,z^2],[x^3,y^3,z^3]|=x y z(x-y)(y-z)(z-x)dot

Solve x-y+z=4 , x+y+z=2 , 2x+y-3z=0