I_(n)=int_(1)^(e)(log x)^(n)dx

If I_(n)=int_(1)^(e)(log x)^(n) d x, then I_(n)+nI_(n-1) equal to

If I_(n)=int_(1)^(e)(ln x)^(n)dx(n is a natural number) then I_(2020)+nI_(m)=e, where n,m in N .The value of m+n is equal to

Let I_(n)=int_(1)^(e)(ln x)^(n)dx,n in N Statement II_(1),I_(2),I_(3) is an increasing sequence.Statement II In x is an increasing function.

I_(n)=int_(1)^(e)(log)^(n)dx and I_(n)=A+BI_(n+1) then A&B=

If I_(n)=int_(1)^(e)(log_(e)x)^(n)dx(n is a positive number),I_(2012)+(2012)I_(2011)=

If I_(m)=int_(1)^(e)(ln x)^(m)dx,m in N, then I_(10)+10I_(9) is equal to (A) e^(10)(B)(e^(10))/(10)(C)e(D)e-1

If for n ge 1, P_(n) = int_(1)^( e) (log x)^(n) dx , then P_(10) - 90P_(8) is equal to

If = int_(1)^(e) (logx)^(n) dx, "then"I_(n)+nI_(n-1) is equal to

If = int_(1)^(e) (logx)^(n) dx, "then"I_(n)+nI_(n-1) is equal to