`2a^2+bc-2ab-ac`

Factorize the following expressions a^2+b^2-2(ab+bc-ac)

Compute the following: [[a^2+b^2, b^2+c^2],[a^2+c^2, a^2+b^2]]+[[2ab, 2bc],[-2ac, -2ab]]

If a=24, b=26, c=28, then the value of a^2+b^2+c^2-ab-bc-ac will be :

If ∣ -a a^2 ab ac ab -b^2 bc ac bc -c^2 | = ka^2b^2c^2 , then k is equal to

If a^2+b^2+c^2=ab+bc+ac then the value of (a+c)/b is:- यदि a^2+b^2+c^2=ab+bc+ac हो, तो (a+c)/b का मान क्या होगा ?

Compute the following: [[a^2+b^2, b^2+c^2],[a^2+c^2, a^2+b^2]] + [[2ab,2bc],[-2ac,-2ab]]

Compute the following: : [[a^2+b^2,b^2+c^2],[a^2+c^2,a^2+b^2]] + [[2ab,2bc],[-2ac,-2ab]]

Compute the following: [[a^2+b^2, b^2+c^2],[a^2+c^2, a^2+b^2]] + [[2ab,2bc],[-2ac,-2ab]]

If a = 24, b = 26, c = 28 , then the value of a^2 + b^2 + c^2 - ab - bc - ac will be