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" Eraluale "quad tan^(-1)1+tan^(-1)2+tan...

" Eraluale "quad tan^(-1)1+tan^(-1)2+tan^(-1)3

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tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)2-tan^(-1)1=tan^(-1)(1/3)

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

Evaluate : tan^(-1)1+tan^(-1)2+tan^(-1)3 .

The value of tan^(-1)1+tan^(-1)2+tan^(-1)3 is

The value of tan^(-1)1+tan^(-1)2+tan^(-1)3 is

Prove that : tan^(-1) 1 + tan^(-1) 2 + tan^(-1) 3= pi = 2(tan^(-1) 1 + tan^(-1)((1)/(2)) + tan^(-1)( (1)/(3)))