Dimensional formula of force hjuis `F=[M^(1)L^(1)T^(2)]` Now we have convert M.K.S system into C.G.S system M=1kg L=1m T=1s (M.k.S) M=1g L=1cm T=1s (C.G.S) `F=M^(1)L^(1)T^(2)` `F(SI)=[1 kg][1m][s^(-2)]=[10^(3)g][10^(2)][s^(-2)]=10^(5)`dynes
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Convert 1 newton (SI unit of force) into dyne (CGS unit of force)
The unit of force in SI system is newton and it is given as 1 newton = 1kg m s^(-2) . In CGS system its unit is dyne and it is given as 1 dyne = 1 g cm s^(2). Arrange the following steps in a sequential order to relate the SI unit and CGS unit of force. (a) Write the conversations of kg and m, into g and cm, respectively. (b) Substitute the conversations in 1 newton = 1 kg m s^(2) Write the relation between 1 newton and dyne. (d) Write in place of 1 g cm s^(-2) as 1 dyne
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