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Consider the following data : 10 MSDs = ...

Consider the following data : `10 MSDs = 1 cm , 10 VSDs = 9 MSDs`, zero of vernier scale is to the right of the zero marking of the main scale with `6 VSDs` coinciding with `MSDs` and the actual reading for length measurement is `4.3 cm with 2 VSDs` coinciding with main scale graduations . Estimate the length.

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In this case, vernier constant = (1mm/10) = 0.1 mm = 0.01 cm Zero error = 6 `xx` 0.1 = + 0.6 mm = 0.06 cm Correction = -0.6 mm = -0.06 cm Actual length = (4.3 + 2 `xx` 0.01) + correction = 4.32-0.06 = 4.26 cm
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