Home
Class 12
PHYSICS
In the equation y = A sin (omega t - kx)...

In the equation `y = A sin (omega t - kx),` obtain the dimensional formula of `omega and k.` Given x is distnace and t is time.

Text Solution

Verified by Experts

The given equation is
y=Asin`(omegat-kx)`
The augment of a trigonometrical function i.e angle is dimensionless i.e, `omegat=theta`
`omega=theta/t=1/T=T^(-1)=[M^(0)L^(0)T^(-1)]`
Also kx=`theta`
`k=(theta)/(x)=(1)/(L)=L^(-1)=[M^(0)L^(-1)T^(0)]`
Promotional Banner

Topper's Solved these Questions

  • GENERAL PHYSICS

    FIITJEE|Exercise SOLVED PROBLEMS (OBJECTIVE)|10 Videos

  • GENERAL PHYSICS

    FIITJEE|Exercise Exercise|9 Videos

  • GENERAL PHYSICS

    FIITJEE|Exercise MATRIX MATCH TYPE|3 Videos

  • FLUID MECHANICS

    FIITJEE|Exercise ASSIGHNMENT COMPREHENSION NUMERICAL BASED QUESTIONS|2 Videos

  • GMP ASSESMENT

    FIITJEE|Exercise Numerical Based|61 Videos

Similar Questions

Explore conceptually related problems

In the relation y = r sin ( omega t - kx) , the dimensions of omega//k are

In the relation, y =rsin(w + kx),the dimensional formula for kx or cot is same as

What are the dimensional formulae of omega and K in the relation y=Asin(omegat-Kx) ?

In the relation ( dy)/( dt) = 2 omega sin ( omega t + phi_(0)) , the dimensional formula for omega t + phi_(0) is

if y = A sin(omega t - kx) , then the value of (dy)/(dx) is

In a wave equation, given by y = A sin (omega t - Kx), y cannot represent

The equation y=A sin^2 (kx-omega t) represents a wave with

The displacement of a progressive wave is represented by y = A sin (omegat - kx), where x is distance and t is time. Write the dimensional formula of (i) omega and (ii) k.

In a wave motion y = sin (kx - omega t),y can represent :-