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epsilon(0)E^(2) has the dimensions of ...

`epsilon_(0)E^(2)` has the dimensions of
(`epsilon_(0)=` permittivity of free space, `E=` electric field)
Here `k=` Boltzmann consant
`T=` absolute temperature
`R=` universal gas constant.

Answer

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Knowledge Check

  • The dimensions of 1/2 epsilon_(0)E^(2) (epsilon_(0)= permittivity of free space, E= electric field) is

    A
    `[MLT^(-1)]`
    B
    `[ML^(-1)T^(-2)]`
    C
    `[MLT^(-2)]`
    D
    `[ML^(2)T^(-1)]`

  • The dimensions of 1/2 in_(0) E^(2) ( in_(0) : permittivity of free space, E: electric field) is-

    A
    `[MLT^(-1)]`
    B
    `[ML^(2)T^(-2)]`
    C
    `[ML^(-1)T^(-2)]`
    D
    `[ML^(2)T^(-1)]`

  • The dimension of ((1)/(2))epsilon_(0)E^(2) ( epsilon_(0) : permittivity of free space, E electric field

    A
    (a) `MLT^(-1)`
    B
    (b) `ML^(2)T^(2)`
    C
    ( c ) `ML^(-1)T^(-2)`
    D
    ( d ) `ML^(2)T^(-1)`

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    Find the dimension of epsilon_(0)E^(2) , where epsilon_(0) is permittivity of free space and E is the electricity field

    The dimensional formula of permittivity (epsilon_0) of free space is :

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    (E^(2))/(mu_(0)) has the dimensions ( E= electric field, mu_(0)= permeabililty of free space)

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