In the experiment of verification of Ohm's law the error in the current measurement is 1%, while that in the voltage measurement is 2%. The error in the resistance has a maximum value of

Options

A. 1%
B. 2%
C. 3%
D. none of these

Answer

To find the maximum error in resistance when verifying Ohm's law, we can follow these steps:

### Step-by-Step Solution:

1. **Understand Ohm's Law**:
Ohm's law states that \( R = \frac{V}{I} \), where \( R \) is resistance, \( V \) is voltage, and \( I \) is current.

2. **Identify the Errors**:
- The error in current measurement \( \left( \frac{\Delta I}{I} \right) \) is given as 1%.
- The error in voltage measurement \( \left( \frac{\Delta V}{V} \right) \) is given as 2%.

3. **Calculate the Relative Error in Resistance**:
The formula for the relative error in resistance \( \left( \frac{\Delta R}{R} \right) \) can be derived from the errors in voltage and current:
\[ \frac{\Delta R}{R} = \frac{\Delta V}{V} + \frac{\Delta I}{I} \]

4. **Substituting the Values**:
- Substitute the percentage errors into the equation:
\[ \frac{\Delta R}{R} = 2\% + 1\% = 3\% \]

5. **Conclusion**:
The maximum error in resistance is 3%.

### Final Answer:
The maximum error in resistance is **3%**.

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