A neutron with kinetic energy K=10 MeV activates a nuclear recation,`n+ ^(12)C rarr ^(9)Be +alpha` whose threshold `E_(th)=6.17 MeV` .Find the kinetic energy of the alpha particles outgoing at right angles to the direction of the incoming neutron.[Take `mu=931.1 MeV`]

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the Reaction and Given Data
We have a neutron (n) colliding with a carbon-12 nucleus (12C) to produce a beryllium-9 nucleus (9Be) and an alpha particle (α). The kinetic energy of the incoming neutron (K) is given as 10 MeV, and the threshold energy (E_th) for the reaction is 6.17 MeV.

### Step 2: Calculate the Available Energy for the Reaction
The available energy (Q) for the reaction can be calculated using the formula:
\[ Q = K - E_{th} \]
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