The stationary `Pb^(200)` nucleus emits an `alpha` with a K.E. ,K=5.77 Me V.Find the recoil velocity of daughter nucleus.What fraction of the total energy liberated in this decay is accounted for by the recoil energy of the daughter nucleus?

Explanation

To solve the problem, we will follow these steps:

### Step 1: Understand the Problem
We have a stationary lead-200 nucleus that emits an alpha particle with a kinetic energy (K.E.) of 5.77 MeV. We need to find the recoil velocity of the daughter nucleus (lead-196) and the fraction of the total energy liberated in this decay that is accounted for by the recoil energy of the daughter nucleus.

### Step 2: Identify the Masses
- The mass of the alpha particle (He nucleus) is approximately 4 atomic mass units (u).
- The mass of the daughter nucleus (lead-196) is approximately 196 atomic mass units (u).
...