Half-life of a radioactive substance `A` is two times the half-life of another radioactive substance `B`. Initially, the number of `A` and `B` are `N_(A)` and `N_(B)`, respectively . After three half-lives of `A`, number of nuclei of both are equal. Then, the ratio `N_(A)//N_(B)` is .
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Let number of c-decays are x and number of `beta`-decays are y. Then 92 - 2x + y = 85 or, 2x - y = 7 .. (1) and 238 - 4x = 210 X = 7 Substituting this value in equation (1), we get y=7
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