The wavelengths and frequencies of photons in transition 1,2 and 3 for hydrogen like atom are `lambda_(1),lambda_(2),lambda_(3), v_(1),v_(2)` and `v_(3)` respectively. Then:
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Hydrogen (H) , deuterium (D) , singly ionized helium (He^(+)) and doubly ionized lithium (Li) all have one electron around the nucleus. Consider n = 2 to n = 1 transition. The wavelength of emitted radiations are lambda_(1), lambda_(2), lambda_(3) and lambda_(4) respectively. then approximately
The wavelengths of photons emitted by electron transition between two similar leveis in H and He^(+) are lambda_(1) and lambda_(2) respectively. Then :-
The wavelength of the short radio waves, microwaves, ultraviolet waves are lambda_(1),lambda_(2) and lambda_(3) , respectively, Arrange them in decreasing order.
The wavelength of K_(a) , X-rays for lead isotopes Pb^(208),Pb^(206),Pb^(204)" are"lambda_(1),lambda_(2)" and"lambda_(3), resperctively. Then
A wave enters to water form air. In air frequency, wavlength intensity and velocity n_(1),lambda_(1),I_(1) and v_(1) resqectively In water the corresponding quantities are n_(2),lambda_(2),I_(2) and v_(2) repectively, then
If the points A(lambda, 2lambda), B(3lambda,3lambda) and C(3,1) are collinear, then lambda=
Cut off potential for a metal in photoclectric effect for light of wavelength lambda_(1), lambda_(2) and lambda_(3) is found to be V_(1),V_(2) and V_(3) volts , If V_(1),V_(2) and V_(3 are in Arithmetic progression then lambda_(1),lambda_(2) and lambda_(3) will be in
Cut off potentials for a metal in photoelectric effect for light of wavelength lambda_(1), lambda_(2) and lambda_(3) is found to be V_(1), V_(2) and V_(3) volts if V_(1), V_(2) and V_(3) are in Arithmetic Progression and lambda_(1), lambda_(2) and lambda_(3) will be :
A particle moving with kinetic energy E_(1) has de Broglie wavelength lambda_(1) . Another particle of same mass having kinetic energy E_(2) has de Broglie wavelength lambda_(2). lambda_(2)= 3 lambda_(2) . Then E_(2) - E_(1) is equal to
