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In the nuclear reaction Mg_12^(24) + He_2^4 to n_0^1 + (?) The product nucleus is
In the nuclear reaction ._(7)^(14)N+X to ._(6)^(14)C+._(1)^(2)H , the X will be
In the nuclear raction ._1H^2 +._1H^2 rarr ._2He^3 +._0n^1 if the mass of the deuterium atom =2.014741 am u , mass of ._2He^3 atom =3.016977 am u , and mass of neutron =1.008987 am u , then the Q value of the reaction is nearly .
What is X in the nuclear reaction ._(7)N^(14) + ._(1)H^(1) rarr ._(8)O^(15) + X
Find the Q - value for the nuclear reaction: ._(2)He^(4)+._(7)N^(14) rarr ._(8)O^(17)+._(1)H^(1) m(._(2)He^(4))=4.0039 "amu" m(._(7) N^(14))=14.0075 "amu" m(._(8)O^(17))=17.0045 amu m(._(1)H^(1))=1.0082 amu
In the nuclear decay given below ._Z^A X rarr ._(Z-1).^A Y rarr ._(Z-1)^(A - 4) B^** rarr ._(Z-1)^(A-1) B , the particle emitted in the sequence are
The binding energy per nucleon of ._(3)^(7) Li and ._(2)^(4)He nuclei are 5.60 MeV and 7.06 MeV, respectively. In the nuclear reaction ._(3)^(7)Li+._(1)^(1)H rarr ._(2)^(4)He+._(2)^(4)He+Q , the value of energy Q released is