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[" 4.In a "/ABC" .if "/A=60^(@),/B=80" '...

[" 4.In a "/_ABC" .if "/_A=60^(@),/_B=80" 'and the bisectors of "/_B" and "/_C" meet at "0.1],[" then "/_BOC=],[" O "60^(@)],[" O "120^(@)],[" O "150^(@)],[" O "30^(@)]

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In a ABC, if /_A=60^(@),/_B=80^(@) and the bisectors of /_B and /_C meet at O, then /_BOC=60^(@)(b)120^(@)(c)150^(@)(d)30^(@)

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