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[" Q.",cos^(6)A+sin^(6)A=1-k sin^(2)(2A)...

[" Q.",cos^(6)A+sin^(6)A=1-k sin^(2)(2A)rArr k=]

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cos^(6)A+sin^(6)A=1-3/4sin^(2)(2A)

cos^(6)A+sin^(6)A=1-3/4sin^(2)(2A)

cos^6A-sin^6A=cos2A(1-1/4sin^2 2A)

cos^(6) A + sin^(6) A = 1 - k sin^2 (2A) implies k =

sin^(6)A + cos^(6)A + 3sin^(2)A.cos^(2)A=

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sin ^ (6) A + cos ^ (6) A = 1-3sin ^ (2) A cos ^ (2) A

cos ^ (3) A sin3A + sin ^ (3) A cos3A = k sin4A rArr k =