" a) "(-2)times(3+5)=-2times8=-16

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

((5^(3))^(-2)times(5^(2))^(-3)times(6)^(5))/((2)^(3)times(3)^(2)times(5)^(5))

Is [(-5)times2)]times3 = (-5)times[(2times3)] ?

(4^(5)times a^(8)times b^(3))/(4^(5)times a^(5)times b^(2))

(6^(3)times7^(4)times8^(5))/(4^(3)times9^(2)times16)

Show that : ( -8/7 ) times [ 3/2 times ( -5/3 ) ] = [ ( -8/7 ) times 3/2 ] times ( -5/3 )

Evaluate : 2/3 times ( 4/5 + 7/8 ) = ( 2/3 times 4/5 ) + ( 2/3 times 7/8 )

Evaluate ( 2^8 times a^5 times b^3 )/ ( ( 4^2 times a^2 times b )

Evaluate : 2/3 times 8/3 times 5/2 times 6/3

Solve : 5/9 times 6/3 + 4/5 times 6/3 - 1/2 times 4/8 + 1/2