[3x-2y=12],[4x-5y=16]

The minimum value of p for which the lines 3x-4y=2, 3x-4y=12, 12x+5y=7 and 12x+5y=p constitute the sides of a rhombus is

The maximum value of p for which the lines 3x-4y=2, 3x-4y=12, 12x+5y=7 and 12x+5y=p constitute the sides of a rhombous is

The minimum value of p for which the lines 3x-4y=2, 3x-4y=12, 12x+5y=7 and 12x+5y=p constitute the sides of a rhombus is

x+2y+4=0,3x=-4y-16

Solve the following simultaneous equations by Graphical method : 4x-y=6, 3x + 5y=16

Solve: 2x-y+z=4,x+3y+2z=12,3x+2y+3z=16

4x -5y-11z=12,. x-3y+z=1 2x + 3y-7z = 2

show the system of equatoins graphically 4x+3y=6, 2x-5y=16.