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[(1)/(65.290^(@))+(1)/(sqrt(3)sin250^(@)...

[(1)/(65.290^(@))+(1)/(sqrt(3)sin250^(@))=lambda],[" then "3 lambda^(2)=?]

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(1)/(cos290^(@)+)(1)/(sqrt(3)sin250^(@))=

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(1)/(cos 290^(@)) + (1)/(sqrt(3)sin 250^(@)) = lambda "then" 3 lambda^(2) =

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If (1)/(cos 290^(@))+(1)/(sqrt(3)sin 250^(@))=lambda , then the value of 9 lambda^(4)+81 lambda^(2)+97 must be

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1/(cos290^@)+1/(sqrt3sin250^@)=lamda then 3lamda^2 =