In the figure shown a semicircular area is removed from a uniform square plate of side `l` and mass ‘m’ (before removing). The x-coordinate of centre of mass of remaining portion is (The origin is at the centre of square)

A disc of radius a/2 is cut out from a uniform disc of radius a as shown in figure . Find the X Coordinate of centre of mass of remaining portion

From a uniform square plate the shaped portions are removed as shown in figure. The coordinates of centre of mass of the remaining plate are x,y Axes and origon are shown in figure.

From a uniform square plate the shaped portions are removed as shown in figure. The coordinates of centre of mass of the remaining plate are x,y Axes and origon are shown in figure.

From a uniform square plate of side a and mass m , a square portion DEFG of side (a)/(2) is removed. Then, the moment of inertia of remaining portion about the axis AB is

From a uniform square plate of side a and mass m , a square portion DEFG of side (a)/(2) is removed. Then, the moment of inertia of remaining portion about the axis AB is

A square of side a/2 is removed from a disc having radius a . Find centre of mass of remaing portion.

A square of side a/2 is removed from a disc having radius a . Find centre of mass of remaing portion.

A semicircular portion of radius 'r' is cut from a uniform rectangular plate as shown in figure. The distance of centre of mass 'C' of remaining plate, from point 'O' is

A semicircular portion of radius 'r' is cut from a uniform rectangular plate as shown in figure. The distance of centre of mass 'C' of remaining plate, from point 'O' is

Figure shows a square plate of uniform thickness and side length sqrt 2 m . One fourth of the plate is removed as indicated. The distance of centre of mass of the remaining portion from the centre of the original square plate is