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[" 4."tan[(pi)/(4)+x]=(1+log x)/(1-tan^(...

[" 4."tan[(pi)/(4)+x]=(1+log x)/(1-tan^(2)x)],[rArr" HS "tan[(pi)/(4)+4]]

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" tan " ((pi)/(4) +x) =(1 + tan x)/(1-tan x)

" tan " ((pi)/(4) -x) =(1 - tan x)/( 1+ tan x)

tan^(-1)(x/2)+tan^(-1)(x/3)=(pi)/(4)

(tan(pi/4+x))/(tan(pi/4-x)) = ((1+tanx)/(1-tanx))^(2)

(tan(pi/4+x))/(tan(pi/4-x)) = ((1+tanx)/(1-tanx))^(2)

tan^(-1)(x-1)+tan^(-1)(x+1)=(pi)/(4)

Solve tan^(-1)x -"tan"^(-1)(1)/(4)=(pi)/(4) .

If 0 lt x lt (pi)/(4), then sec 2x - tan 2x= ................ A) tan (x- (pi)/(4)) B) tan ((pi)/(4) -x) C) tan (x+(pi)/(4)) D) tan ^(2) (x+ (pi)/(4))

int_(0)^(pi//4) log (1+tan x) dx =?