5([1,be,a(b+e)],[1,ca,b(e+a)],[1,ab,e(a+b)])=0

det[[1,bc,bc(b+c)1,ca,ca(c+a)1,ab,ab(a+b)]]=0

|{:(1,bc,bc(b+c)),(1,ca,ca(c+a)),(1,ab,ab(a+b)):}|=0

If A , B ,C are angles of a triangle, then the value of |[e^(2i A),e^(-i C),e^(-i B)],[e^(-i C),e^(2i B),e^(-i A)],[e^(-i B),e^(-i A),e^(2i C)]| is (a) 1 (b) -1 (c) -2 (d) -4

If A , B ,C are angles of a triangles, then the value of |[e^(2i A),e^(-i C),e^(-i B)],[e^(-i C),e^(2i B),e^(-i A)],[e^(-i B),e^(-i A),e^(2i C)]| is 1 b. -1 c. -2 d. -4

If A , B ,C are angles of a triangle, then the value of |[e^(2i A),e^(-i C),e^(-i B)],[e^(-i C),e^(2i B),e^(-i A)],[e^(-i B),e^(-i A),e^(2i C)]| is (a) 1 (b) -1 (c) -2 (d) -4

If A , B ,C are angles of a triangles, then the value of |[e^(2i A),e^(-i C),e^(-i B)],[e^(-i C),e^(2i B),e^(-i A)],[e^(-i B),e^(-i A),e^(2i C)]| is 1 b. -1 c. -2 d. -4

The domain of f(x) is (0,1)dot Then the domain of (f(e^x)+f(1n|x|) is a. (-1, e) (b) (1, e) (c) (-e ,-1) (d) (-e ,1)

The domain of f(x) is (0,1) Then the domain of (f(e^x)+f(1n|x|) is (a) (-1, e) (b) (1, e) (c) (-e ,-1) (d) (-e ,1)