[(1)/(x)+(1)/(y)=(1)/(24)],[(2)/(x)+(1)/(y)=(1)/(8)]

Solve for x and y : (1)/(2x) - (1)/(y) = - 1, (1)/(x) + (1)/(2y)= 8 ( x ne 0 , y ne 0 )

Solve the following system of equations: (1)/(3x+y)+(1)/(3x-y)=(3)/(4),quad (1)/(2(3x+y))-(1)/(2(3x-y))=-(1)/(8)

(1) / (2x) - (1) / (y) = - 1, (1) / (x) + (1) / (2y) = 8

Solve the following pairs of equations: (1)/(2x)-(1)/(y)=-1, (1)/(x)+(1)/(2y)= -8, x, y ne 0

The solution of (dy)/(dx)=(1)/(2x-y^(2)) is given by , (A) y=Ce^(-2x)+(1)/(4)x^(2)+(1)/(2)x+(1)/(4)," 4"(1)/(2)," (B) "x=Ce^(-y)+(1)/(4)y^(2)+(1)/(4)y+(1)/(2)," (C) "x=Ce^(y)+(1)/(4)y^(2)+y+(1)/(2)," (D) "x=Ce^(2y)+(1)/(2)y^(2)+(1)/(2)y+(1)/(4)

(x+1)/(2)+(y-1)/(3)=8;(x-1)/(3)+(y+1)/(2)=9

If 2^(x)=4^(y)=8^(z) and ((1)/(2x)+(1)/(4y)+(1)/(6z))=(24)/(7) , then find the value of z.

Solve the following simultaneous equations. (1)/(3x + y) + (1)/(3x - y) = (3)/(4) , (1)/(2(3x + y)) - (1)/(2(3x - y)) = - (1)/(8)

2^(x)=4^(y)=8^(z) and (1)/(2x)+(1)/(4y)+(1)/(4z)=4

(1) / (3x + y) + (1) / (3x-y) = (3) / (4) (1) / (2 (3x + y)) - (1) / (2 (3x-y) )) = - (1) / (8)