" (26."a^(3)-(1)/(a^(3))-2a+(2)/(a)

Factorise : a^(3)+(1)/(a^(3))+(26)/(27)

(26.57)^(1//3)

Find (26)^((1)/3)).

2x+(8)/(3)=(26)/(3)-x

If A={:[(3,2),(0,1)]:}" then:(A^(-1))^(3)= ...a) (1)/(27)[(1,-26),(0,27)] b) (1)/(27)[(-1,26),(0,27)] c) (1)/(27)[(1,-26),(0,-27)] d) (1)/(27)[(-1,-26),(0,-27)]

If X=a^(1)b^(2)c^(3)...z^(26) and Y=z^(1)y^(2)x^(3)...a^(26) where,abcd...z=54sqrt(64), then find XY.

(26)^(2)+(32)^(2)+?=(64)^(2)(1)2246(2)2396(3)2276(4)2386

The value of (6^(n+3) - 32.6^(n+1))/(6^(n+2) - 2.6^(n+1)) is equal to