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int e^(tan theta)(sec theta-sin theta)d ...

int e^(tan theta)(sec theta-sin theta)d theta=

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value of e^(tan theta)(sec theta-sin theta)d(theta) is equal to

int(sec theta)/(sec theta-tan theta)d theta

int (tan theta d theta)/(1-sin theta)

int (tan theta d theta) / (1-sin theta)

(cos theta)/(sec theta-tan theta)=1+sin theta

Prove: (tan theta)/(sec theta-1)=(tan theta+sec theta+1)/(tan theta+sec theta-1)

(sec theta+tan theta)/(sec theta-tan theta)+(sec theta-tan theta)/(sec theta+tan theta)

If 5 sin theta =3, then (sec theta+ tan theta)/(sec theta- tan theta) is equal to

If 5 sin theta =3, then (sec theta+ tan theta)/(sec theta- tan theta) is equal to

(tan theta+sin theta)/(tan theta-sin theta)=(sec theta+1)/(sec theta-1)