(40)/(x+y)+(2)/(x-y)=5,(25)/(x+y)-(3)/(x-y)=1

(14)/(x+y)+(3)/(x-y)=5,(21)/(x+y)-(2)/(x-y)=1

(4)/(x-y) + (1)/(x + y) = 3 , (2)/(x - y) - (3)/(x + y) = 5

Solve for x and y 2/(3x+2y)+3/(3x-2y)=17/5,5/(3x+2y)+1/(3x+2y)=6/5

Solve for x and y 2/(3x+2y)+3/(3x-2y)=17/5 5/(3x+2y)+1/(3x-2y)=2

Find the products: (3/x-5/y)(9/(x^2)+(25)/(y^2)+(15)/(x y))

Simplify the following:(x-2y) (y-3x)+(x+y) (x-3y)- (y-3x)(4x-5y).

Find the following products and verify the result for x=-1,y=-2:(3x-5y)(x+y)(2)(x^(2)y-1)(3-2x^(2)y)((1)/(3)x-(y^(2))/(5))((1)/(3)x+(y^(2))/(5))

The locus of a point "P" ,if the join of the points (2,3) and (-1,5) subtends right angle at "P" is x^(2)+y^(2)-x-8y+13=0 x^(2)-y^(2)-x+8y+3=0 x^(2)+y^(2)-4x-4y=0,(x,y)!=(0,4)&(4,0) x^(2)+y^(2)-x-8y+13=0,(x,y)!=(2,3)&(-1,5)

Simplify : (i) (5x - 9y) - (-7x + y) (ii) (x^(2) -x) -(1)/(2)(x - 3 + 3x^(2)) (iii) [7 - 2x + 5y - (x -y)]-(5x + 3y -7) (iv) ((1)/(3)y^(2) - (4)/(7)y + 5) - ((2)/(7)y - (2)/(3)y^(2) + 2) - ((1)/(7)y - 3 + 2y^(2))