There are 24 balls in a pot. If 3 of them are Red, 5 of them are Blue and the remaining are Green then, what is the probability of picking out (i) a Blue ball, (ii) a Red ball and (iii) a Green ball ?

Explanation

n(S) = 24
Red - n(R) = 3
Blue - n(B) = 5
Green - n (G) = 16
(i) Probability of picking a Blue ball ` = (n(B))/(n(S)) = (5)/(24)`
(ii) Probability of picking a Red ball =`(n(R))/(n(S)) = (3)/(underset(8)cancel(24)) = (2)/(3)`
(iii) Probability of picking a Green ball `= (n(G))/(n(S)) = (overset(2)cancel(16))/(underset(3)cancel(24))=(2)/(3)`