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What is the probability that the spinner...

What is the probability that the spinner will not land on a multiple of 3 ?

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Total no. of choices n(S) = 8
Total no. multiples of 3 A = {3 , 6}
n(A) = 2
Event of non-multiples of 3B = {1, 2, 4, 5, 7, 8}
n(B) = 6
`:. P(B) = (n(B))/(n(S)) = (overset(3)cancel(6))/(underset(4)cancel(8)) = (3)/(4)`
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