One card is drawn from a pack of 52 cards, each of the 52 cards being equally likely to be drawn. Find the probability that the card drawn is
(i) an ace,
(ii) either red card or king .

Explanation

(i) Probability of ace `= (cancel(4))/(underset(13)cancel(52))=(1)/(13)`
Probability of red ` = (cancel(26))/(underset(2)cancel(52))= (1)/(3)`
Probability of king ` = (cancel(4))/(underset(13)cancel(52)) = (1)/(13)`
Probability of red king ` = (cancel (2))/(underset(26)cancel(52))= (1)/(26)`
(ii) Probability of red or king `=(1)/(2)+(1)/(13)-(1)/(26)=(13+2-1)/(26)=(overset(7)cancel(14))/(underset(13)cancel(26))=(7)/(13)`