Home
Class 12
PHYSICS
The parallax of a heavenly body measured...

The parallax of a heavenly body measured from tow points diametrically opposite on equator of earth is 2.0 minute. If radius of earth is 6400 km, calculate distance of heavenly body.

Text Solution

Verified by Experts

Angle of parallx `theta` = 2 minute
= `2xx(1/60)^(2)`
`rArr0=2xx1/60xxpi/180"rad"" "[because1^(@)-pi/180"rad"]`
`theta=pi/(5400)"rad"`
From parallax method
`BP=(AB)/theta`
`rArrBP=("Diameter of earth")/theta`
`rArrBP=(2xx6400)/((pi/5400))km`
`rArrBP=2.2xx10^(7)km`
`=2.2xx10^(10)m`
Promotional Banner

Similar Questions

Explore conceptually related problems

The parallex of a heavenly body measured ffrom two points diametrically opposite on equater of earth is 1.0 minutes. If the radius of the earth is 6400 m, find the distance of the heavenly body from the centre of the earth in AU. Given 1 AU=1.5xx10^(11) m.

Find the velocity of a satellite at height 80 km from earth. If the radius of earth is 6400 km

What should be the length of the day so that the weight of a body on the equator of earth becomes zero ? Given that radius of earth is 6400 km and acceleration due to gravity on its surface is 9.8 m//s^(2)

The angular speed of earth is "rad s"^(-1) , so that the object on equator may appear weightless, is (radius of earth = 6400 km)

What is the linear velocity of a body on the surface of the earth at the equator ? Given the radius of the earth is 6400 km . Period of rotation of the earth = 24 hours.

The energy required for a body of mass 1000 kg to escape from the attraction of the earth is (If radius of the earth is 6400 km and g=10m//s^(2) )

What is the linear velocity of a person at equator of the earth due to its spinning motion? (Radius of the earth =6400km )

A distant star is observed from two diametrically opposite points on earth. If both the points are at distance 1.27xx10^(7)m and angle subtended by both the points at star is 0.80'' , calculate the distance between earth and the star.

The moon subtends an angle of 57 minutes at the base line equal to radius of earth. What is the distance of moon from earth. Given radius of earth is 6400 km.