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The dimensional formula for moment of co...

The dimensional formula for moment of couple is

A

`[ML^(2)T^(-2)]`

B

`[MLT^(-2)]`

C

`[ML^(-1)T^(-3)]`

D

`[ML^(-2)T^(-2)]`

Text Solution

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The correct Answer is:
To find the dimensional formula for the moment of a couple, we can follow these steps: ### Step 1: Understand the Concept of Moment of a Couple A couple consists of two equal and opposite forces acting on an object, separated by a certain distance. The moment of a couple is defined as the product of one of the forces and the perpendicular distance between the lines of action of the forces. ### Step 2: Write the Formula for the Moment of a Couple The moment of a couple (M) can be expressed as: \[ M = F \times d \] where: - \( F \) is the force, - \( d \) is the perpendicular distance between the two forces. ### Step 3: Determine the Dimensional Formula for Force Force is defined by Newton's second law as: \[ F = m \times a \] where: - \( m \) is mass, and its dimensional formula is \([M]\), - \( a \) is acceleration, and its dimensional formula is \([L T^{-2}]\). Thus, the dimensional formula for force \( F \) is: \[ [F] = [M][L T^{-2}] = [M L T^{-2}] \] ### Step 4: Determine the Dimensional Formula for Distance The perpendicular distance \( d \) has the dimensional formula: \[ [d] = [L] \] ### Step 5: Combine the Dimensional Formulas Now, substituting the dimensional formulas of force and distance into the formula for the moment of a couple: \[ [M] = [F] \times [d] = [M L T^{-2}] \times [L] \] ### Step 6: Simplify the Expression Combining the dimensions gives: \[ [M] = [M L^2 T^{-2}] \] ### Conclusion The dimensional formula for the moment of a couple is: \[ [M] = [M L^2 T^{-2}] \]
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