In the previous problem. The friction fo...

In the previous problem. The friction force applied by ground on block B is

0 N

20 N

10 N

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A block of mass 1 kg in kept on a rough horizontal surface with mu_(s)=0.1 . A force of 0.5 N is applied as shown in the figure. What is the frictional force applied by ground on the block?

Given in figure are two blocks A and B of weight 20N and 100N, respectively. These are being pressed against a wall by a force F as shown. If the coefficient of friction between the blocks is 0.1 and between block B and the wall is 0.15, the frictional force applied by the wall on block B is:

A man of mass 80kg pushes box of mass 20kg horizontaly. The man moves the box with a constant acceleration of 2 m//s^(2) but his foot does not slip on the ground. There is no friction between the box and the ground. There is no friction between the box and the ground. whereas there is sufficient friction between the man's foot and the ground to prevent him from slipping. Assertion:- The force applied by the man on the box is equal and opposite to the force applied by the force applid by the box on the man. Reason:- Friction force applied by the ground on the man is 200N.

A man of mass 80kg pushes a box of mass 20kg horizontally. The man moves the box with a constant acceleration of 2m//s^(2) but his foot does not slip on the ground. There is no friciton between the box and the ground, whereas there is sufficient friction between the man's foot and the ground to prevent him from slipping. Assertion :- The force applied by the man on the box is equal and opposite to the force applied by the force applied by the box on the man. Reason :- Friction force applied by the ground on the man is 200N .

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If the mass of block is 1 kg and a force of 10 / sqrt3 N is applied horizontally on the block as shown in the figure . The frictional force acting on the block is :

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A block A of mass 4 kg is kept on ground. The coefficient of friction between the block and the ground is 0.8 . The exernal force of magnitude 30 N is applied applied parallel to the ground. The resultant force exernal by the ground on the block is (g = 10 m//s^(2))

AAKASH INSTITUTE-LAWS OF MOTION-EXERCISE

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