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Two bodies of masses `m_(1) " and " m_(2)` are connected a light string which passes over a frictionless massless pulley. If the pulley is moving upward with uniform acceleration `(g)/(2)`, then tension in the string will be

A

`(3m_(1)m_(2))/(m_(1)+m_(2))g`

B

`(m_(1)+m_(2))/(4m_(1)m_(2))g`

C

`(2m_(1)m_(2))/(m_(1)+m_(2))g`

D

`(m_(1)m_(2))/(m_(1)+m_(2))g`

Text Solution

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AAKASH INSTITUTE-LAWS OF MOTION-Assignment (SECTION-A)
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  4. In the figure given below, with what acceleration does the block of ma...

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  5. T(1) and T(2) in the given figure are

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  6. In the arrangement shown, the mass m will ascend with an acceleration ...

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  7. A chain of mass M and length L is held vertical by fixing its upper en...

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  8. A man slides down a light rope whose breaking strength in eta times hi...

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  9. In the arrangement as shown, tension T(2) is (g=10m//s^(2))

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  10. If pulleys shown in the diagram are smooth and massless and a(1) and a...

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  11. Figure shows a uniform rod of length 30 cm having a mass 3.0 kg. The ...

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