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Figure shows tow cases. In first case a ...

Figure shows tow cases. In first case a spring (spring constant K) is pulled by two equal and opposite forces F at both ends and in second case is pulled by a force F at one end. Extensions (x) in the springs will be

A

In both cases `x=(2F)/(K)`

B

In both cases `x=(F)/(K)`

C

In first case `x=(2F)/(K)`, in second case `x=(F)/(K)`

D

In first case `x=(F)/(K)`, In second case `x=(2F)/(K)`

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