Two particles of mass `1kg` and `2kg` are moving along the same line with speeds `2m//s` and `4m//s` respectively. Calculate the speed of the centre of mass of the system if both the particles are moving in the same direction.

Explanation

`V_(cm)=(m_(1)v_(1)+m_(2)v_(2))/(m_(1)+m_(2))`
Substituting the value, we get
`V_(cm)=(1xx2+2xx4)/(3)=(2+8)/(3)=(10)/(3)m//s`.