A particle is moving along a circle of radius `20cm`, with a linear velocity of `2m//s. Calculate the angular velocity of the particle.

Explanation

`vec(v)=vec(omega)xx vec(r )`
As the angle between `vec(r )` and `vec(omega)` is `90^(@)` so the magnitude of linear velocity is `|vec(v)|=r omega`
`omega = (v)/(r )=(2xx100)/(20)=10 rad s^(-1)`.