The angular momentum of a particle changes from `4kg m^(2)s^(-1)` to `8kg m^(2)s^(-1)` is `2` seconds. Calcualte the torque acting on the particle

Explanation

`(dL)/(dt)=(8-4)/(2)=(4)/(2)=2 Nm`
Hint : `vec(tau)=(d vec(L))/(dt)`