Calculate the moment of inertia of a ring about a tangent to the circle of the ring normal to its plane.

Explanation

Moment of inertia of the through CM is `I=MR^(2)`
using parallel axis therom
`I=I_(cm) + Md^(2) `
`d=R "so" I=MR^(2) +MR^(2) =2MR^(2)`