Calculate the moment of inertia of the given rod about an axis CD.

Explanation

Moment of inerita of the rod about `AB=(MI^(2))/(12)
Usa parallel axis therom.
` `I_(C D) =-(Ml^2)/(12) +M((1)/(4))^(2) = (Ml^(2))/(12)+(Ml^(2))/(16) =(7)/(48)Ml^(2)``