The angular velocity of a motor wheel changes from `180` rpm to `300` rpm in `4` seconds. Calculate the no. of revolutions does the engine make during this time.

Explanation

`omega = omega_(0)+alpha t`
`rArr ((300-180))/(60)=alpha xx4`
`rArr alpha = (2)/(4)=0.5 rev//s^(-2)`
using `theta = omega_(0)t+(1)/(2)alpha t^(2)`
`= (180)/(60)xx 4+(1)/(2)xx0.5xx16`
= 16 revolution.