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The moment of inertia of a body moving w...

The moment of inertia of a body moving with angular velocity `omega` decreases from `l` to `(l)/(3)` without any external torque. Calculate the new angular velocity of the body.

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`l_(1)omega_(1)=l_(2)omega_(2)`
`omega_(2)=(l_(1)omega_(1))/(l_(2))=(l omega)/((l)/(3))=3omega`
Hint : `l_(1)omega_(1)=l_(2)omega_(2)`
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